Rather than giving a strict mathematical definition, let us look at an example of a PDE, the heat equation in 1 space dimension
{{∂}^{2}u(x,t)\over
∂{x}^{2}} = {1\over
k} {∂u(x,t)\over
∂t} .
| (1.5) |
{{∂}^{2}u(x,t)\over
∂{x}^{2}} = {1\over
k} {∂u(x,t)\over
∂t} +\mathop{ sin}\nolimits (x)
| (1.7) |
is called inhomogeneous, due to the \mathop{sin}\nolimits (x) term on the right, that is independent of u.
Why is all that so important? A linear homogeneous equation allows superposition of solutions. If {u}_{1} and {u}_{2} are both solutions to the heat equation,
{{∂}^{2}{u}_{1}(x,t)\over
∂{x}^{2}} −{1\over
k} {∂{u}_{1}(x,t)\over
∂t} = {{∂}^{2}{u}_{2}(x,t)\over
∂{x}^{2}} −{1\over
k} {∂{u}_{2}(x,t)\over
∂t} = 0,
| (1.8) |
any combination is also a solution,
{{∂}^{2}[a{u}_{1}(x,t) + b{u}_{2}(x,t)]\over
∂{x}^{2}} −{1\over
k} {∂[a{u}_{1}(x,t) + b{u}_{2}(x,t)]\over
∂t} = 0.
| (1.9) |
For a linear inhomogeneous equation this gets somewhat modified. Let v be any solution to the heat equation with a \mathop{sin}\nolimits (x) inhomogeneity,
{{∂}^{2}v(x,t)\over
∂{x}^{2}} −{1\over
k} {∂v(x,t)\over
∂t} =\mathop{ sin}\nolimits (x).
| (1.10) |
In that case v + a{u}_{1}, with {u}_{1} a solution to the homogeneous equation, see Eq. (1.8), is also a solution,
Finally we would like to define the order of a PDE as the power in the highest derivative, even it is a mixed derivative (w.r.t. more than one variable).
Quiz Which of these equations is linear? and which is homogeneous?
What is the order of the following equations?