11.7 General solutions

One of the reasons for playing such game is that we can rewrite the kinetic energy as

−{{ℏ}^{2}\over 2m}\hat{{p}}^{2}f(r) = −{{ℏ}^{2}\over 2m} {1\over { r}^{2}} {∂\over ∂r}\left ({r}^{2} {∂\over ∂r}f(r)\right ) + {1\over { r}^{2}}\hat{{L}}^{2}f(r).
(11.34)