11.1 The momentum operator as a vector

First of all we know from classical mechanics that velocity and momentum, as well as position, are represented by vectors. Thus we need to represent the momentum operator by a vector of operators as well,

\hat{p} = ({ℏ\over i} {∂\over ∂x}, {ℏ\over i} {∂\over ∂y}, {ℏ\over i} {∂\over ∂z}).
(11.1)

There exists a special notation for the vector of partial derivatives, which is usually called the gradient, and one writes

\hat{p} = {ℏ\over i} \mathop{∇}.
(11.2)

We now that the energy, and Hamiltonian, can be written in classical mechanics as

E = {1\over 2}m{v}^{2} + V (x) = {1\over 2m}{p}^{2} + V (x),
(11.3)

where the square of a vector is defined as the sum of the squares of the components,

{({v}_{1},{v}_{2},{v}_{3})}^{2} = {v}_{ 1}^{2} + {v}_{ 2}^{2} + {v}_{ 3}^{2}.
(11.4)

The Hamiltonian operator in quantum mechanics can now be read of from the classical one,

\hat{H} = {1\over 2m}\hat{{p}}^{2} + V (x) = −{{ℏ}^{2}\over 2m}\left ( {{∂}^{2}\over ∂{x}^{2}} + {{∂}^{2}\over ∂{y}^{2}} + {{∂}^{2}\over ∂{z}^{2}}\right ) + V (x).
(11.5)

Let me introduce one more piece of notation: the square of the gradient operator is called the Laplacian, and is denoted by Δ.